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  • Answers created by Ch - Socratic
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    To solve a problem like this, first determine the limiting reagent, then calculate the number of moles of product, and finally convert to grams of product 1) Write the balanced reaction so you'll know the proper stoichiometric ratios In this case it's easy, but other reactions may be tricky Pb(CH_3COO)_2 + H_2SO_4 rarr PbSO_4 + 2 CH_3COOH 2) Determine which reagent is limiting In this case
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    you would get about 35 8 grams of Br_2 from this reaction Let's begin with balancing our equation and figuring how much we have of everything The reaction between Calcium Bromide and Chlorine will be a single replacement reaction Therefore, we know the reaction will look a little like this: CaBr_2 + Cl_2 -> CaCl_2 + Br_2 Luckily we don't need to try and balance this equation, as it is
  • Question #7a784 - Socratic
    "170 mL" Your strategy here will be to write a balanced chemical equation for this single replacement reaction use the molar volume of a gas at STP to find the number of moles of hydrogen gas present in that volume use the mole ratio that exists between sulfuric acid and hydrogen gas to find the number of moles of the former needed to produce that many moles of the latter use the sulfuric acid
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